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15s^2+10s-40=0
a = 15; b = 10; c = -40;
Δ = b2-4ac
Δ = 102-4·15·(-40)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-50}{2*15}=\frac{-60}{30} =-2 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+50}{2*15}=\frac{40}{30} =1+1/3 $
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